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¿Question #5275?
[Deleted user]: [deleted question]

MonsterMike: x = (-b +/- Sqrt(b**2 - 4ac))/2a gives the two roots to ax**2 + bx + c = 0, if memory serves. A better question is why do I remember crap like this?
aetwitch: yes
MartinWin: For x^2+px+q=0, you get x with the formula: x=-p/2+-sqrt(p^2/4-q).
CSchlobach: Don't know and too lazy to look it up :)
Bjorn DS: [-b +- sqrt(b² - 4*a*c)] / 2a
BeeCeeJay: don't remember anymore, sorry
Marqos: opposite b plus or minus radical four ac minus b squared all over two a?
atrium: y = ax^2 + bx + c
EvinRobertson: \frac{-b \pm \sqrt {b^2-4ac}}{2a}
Polgara: we call it the abc formule (cheated and looked at the answers)
Gamedeity: I'm not doing your homework for you!! :) It's a fairly easy algebra equation -b*square root(blah blah blah
Hector Vortac: Fascinating. I'm answering random questions, and the last one I looked at someone gave the quadratic formula as an answer. The question was about the game Attika.
Boot2daHead: The complex formula used to equate little wooden cubes to victory points. Varies from game to game.
1000rpm: "the"?
dcclark: if ax^2+bx+c = 0, then x=(-b(+/-)Sqrt(b^2-4ac))/2
mrmarcus: ax^2 +bx + c = 0
DHEK: Look up a math textbook. I forgot.
enfanta: Doesn't it take the grey out of your hair gradually?
Brentoon: negative B plus or minus the square root of B squared minus 4 time a times c over 2 times a...............MAN i am proud of myself for remembering that
Leo-T: ax^2+bx+c=0, x = (-b[+-] SQRT(b^2 - 4AC))/2a
scriptorum: Oh, that thing with the 4AC watchamadoohickey.
klarkinhistrep: Answer unclear. Try again later.
DoctorWu: THE quadratic formula? Is there only 1? Perhaps there are 4......
Nils: (-b±√(b²-4ac))/(2a)
bigbadsteve: x-a+gh=whatever
dmomo: Not telling. You have a wap enabled device and are taking a quiz.
interhawk: something I knew once upon a time it has 2ab somewhere I think
GI Joe: (Sung to the tune of pop goes the weasel).... x equals negative b, plus or minus square root, of b squared minus 4ac, all! over 2a.
hacksword: Why do you want to know?
Hoju: math stuff
brainrob: It's a potion you drink that makes you grow 2 extra legs
xlorp: My favorite memory from high-school math classes. So simple, elegant and practical.
Chris Page: It's better to know how to derive it from first principles.
Grizzley91: ax + by = c ?
jasta6: 4x4
djlg: The solution to quadratic equations.
ChaosOrdeal: (a+b)(a+c)=a^2+ab+ac+bc or something like that?
confuse_a_cat: (-b +- sqrt(b^2 - 4ac))/2a
jellospike: See! That's what happens when you ask too many questions.
vetinari7878: That's the formula for finding the roots of a quadratic equation? Something like x = [-b +- sqrt(b^2 - 4a*c)] / 2a .
Igloo cool: The sum of the squares of the legs of a right triangle is equal to the square of the hypotenuse
Loquutus: ouch. Now I have a headache.
POvidiusNaso: -b2 +/- (sq rt of -b - 4ac)/2a ? Some nonsense like that.
Cavedog_pdx: Clark has it right
dietevil: I don't have the keys to effectively express it
ssmooth: Oh please
CortexBomb: That is something that I do not need to know, and will not think of again
Lord_Prussian: Algebra, ugh
MisterCranky: It's a formula used to solve quadratic equations, obviously.
jttm: Is that the thing which makes 4 rats?
skelebone: I only recall about half of it, so it's more like the octilic formula.
CDRodeffer: If the generic quadratic form is ax^2 + bx + c = 0, then the formula to solve for x is x = [-b +/- (b^2 - 4ac)^0.5] / 2a.
chaddyboy_2000: I don't remember any of it. Besides, I just had the formula in my graphing calculator anyways.
Spielfreak: ax**2 +bx +c = 0 ?? I'm embarassed I cannot answer this with any certainty.